The curve x = t, y = t² has Cartesian equation y = x², and x = 2t, y = t² gives y = x² ÷ 4, so this Year 13 sheet opens by eliminating the parameter. The key adds x² + y² = 1 as a circle and 1 ÷ t as a gradient.
Key Takeaways
x = t, y = t² gives y = x² (Q1).
x = 2t, y = t² gives y = x² ÷ 4 (Q2).
Q4 records x² + y² = 1 as a Cartesian circle.
Section A: Multiple Choice Questions (1 Mark Each)
Choose the correct option for each question.
1.The curve x = t, y = t² has Cartesian equation:
(a) y = x²(b) y = 2x(c) y = x(d) x = y²
2.The curve x = 2t, y = t² has Cartesian equation:
(a) y = x² ÷ 4(b) y = 4x²(c) y = x²(d) y = 2x²
3.For the curve x = t², y = 2t, the value of dy/dx is:
(a) 1 ÷ t(b) 2t(c) t(d) 1 ÷ (2t)
4.The curve x = cos θ, y = sin θ has Cartesian equation:
(a) x² + y² = 1(b) x + y = 1(c) x² + y² = 2(d) y = x
5.For the curve x = t², y = 2t, the gradient at t = 1 is:
(a) 1(b) 2(c) ½(d) 3
6.The curve x = 3 cos θ, y = 3 sin θ has Cartesian equation: