Dividing x³ − 2x + 3 by (x − 1) leaves a remainder of 2, while f(x) = x³ − x² − 4x + 4 breaks apart with (x − 1), and these two results frame the factor and remainder work here. A proof that √2 is irrational completes the key's algebra.
Key Takeaways
The remainder theorem gives remainder 2 when x³ − 2x + 3 is divided by (x − 1) (Q1).
(x − 1) factors f(x) = x³ − x² − 4x + 4 (Q2).
The irrationality proof of √2 assumes a and b share no common factor.
Section A: Multiple Choice Questions (1 Mark Each)
Choose the correct option for each question.
1.The remainder when x³ − 2x + 3 is divided by (x − 1) is:
(a) 2(b) 1(c) 0(d) 3
2.Which of the following is a factor of f(x) = x³ − x² − 4x + 4?
(a) (x − 1)(b) (x + 1)(c) (x − 4)(d) (x + 4)
3.When f(x) is divided by (x − a), the remainder is:
(a) f(a)(b) f(−a)(c) f(x) ÷ a(d) 0
4.A proof by contradiction that √2 is irrational begins by assuming:
(a) √2 = a ÷ b where a and b are integers with no common factor(b) √2 is irrational(c) √2 is greater than 1(d) √2 is a whole number
5.Which number is a counterexample to the statement: all prime numbers are odd?
(a) 2(b) 1(c) 3(d) 9
6.In the proof that √2 is irrational, from √2 = a ÷ b you obtain a² = 2b², so a² is even and a is even. Writing a = 2k gives b² = 2k², so b is even too. Why is this a contradiction?
(a) a and b were assumed to have no common factor(b) a and b must both be odd(c) √2 must equal 2(d) 2 is not a prime number
Section B: Short Answer Type Questions (2 Marks Each)
Show all steps clearly.
7.Show that (x − 3) is a factor of f(x) = x³ − 2x² − 5x + 6.
8.Find the remainder when x³ + 2x² − x + 1 is divided by (x − 1).