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On a velocity-time graph the gradient is the acceleration and the area under the graph is the distance travelled, so this Class 9 sheet opens by reading both operations off the two axes. The answers record m/s² and the uniform velocity case.
Key Takeaways
The gradient of a velocity-time graph gives the acceleration (Q1).
The area under the graph gives the distance travelled (Q2).
Q6 records m/s².
Section A: Multiple Choice Questions (1 Mark Each)
Choose the correct option for each question.
1.
On a velocity-time graph, the gradient represents
(a) acceleration (b) distance (c) force (d) speed
2.
The area under a velocity-time graph represents
(a) the distance travelled (b) the acceleration (c) the force applied (d) the momentum
3.
A horizontal line on a velocity-time graph represents
(a) uniform velocity (b) uniform acceleration (c) rest only (d) increasing speed
4.
A straight line sloping upwards on a velocity-time graph represents
(a) uniform acceleration (b) deceleration (c) constant velocity (d) a body at rest
5.
If the gradient of a velocity-time graph is negative, the body is
(a) decelerating (b) accelerating (c) moving with constant speed (d) at rest
6.
The SI unit of acceleration is
(a) m/s² (b) m/s (c) m (d) km/h
Section B: Short Answer Type Questions (2 Marks Each)
Show all steps clearly.
7.
What does the gradient of a velocity-time graph represent?
8.
What does the area under a velocity-time graph represent?
9.
What does a horizontal line on a velocity-time graph mean?
10.
Define uniform acceleration.
11.
A body starts from rest and moves with uniform acceleration. What is its initial velocity?
12.
What does a straight line sloping downwards on a velocity-time graph indicate?
13.
Write the first equation of motion and state the meaning of each symbol.
14.
Write the third equation of motion and state the meaning of each symbol.
Section C: Numericals & Word Problems (3 Marks Each)
Apply the concepts to solve the problems. Show all working.
15.
A body starts from rest and accelerates uniformly at 2 m/s² for 10 s. Using v = u + at, find its final velocity.
16.
A car accelerates uniformly from 10 m/s to 30 m/s in 5 s. Using a = (v − u) ÷ t, find the acceleration.
17.
A body moving at 20 m/s is brought to rest in 4 s. Using a = (v − u) ÷ t, find the acceleration.
18.
A car accelerates from rest at 2 m/s² for 10 s. Using s = ut + ½at², find the distance travelled.
19.
A ball is dropped from rest. Using v² = u² + 2as with g = 10 m/s², find its velocity after falling through 20 m.
20.
A train travelling at 72 km/h is brought to rest in 8 s. Using distance = (u + v) ÷ 2 × t, find the distance travelled.
Answer Key
1. a) acceleration
2. a) the distance travelled
3. a) uniform velocity
4. a) uniform acceleration
5. a) decelerating
6. a) m/s²
7. Refer to solution guide.
8. Refer to solution guide.
9. Refer to solution guide.
10. Refer to solution guide.
11. Refer to solution guide.
12. Refer to solution guide.
13. Refer to solution guide.
14. Refer to solution guide.
15. Refer to solution guide.
16. Refer to solution guide.
17. Refer to solution guide.
18. Refer to solution guide.
19. Refer to solution guide.
20. Refer to solution guide.
End of Worksheet
People Also Ask
What does the gradient of a velocity-time graph represent?
The acceleration, option (a) in this worksheet (Q1).
What does the area under a velocity-time graph represent?
The distance travelled, option (a) in this worksheet (Q2).
What does a straight horizontal line show?
Uniform velocity, option (a) in this worksheet (Q3).