f(5) for f(x) = 3x + 2 comes out as 17 and the vertex of y = x² − 4x + 3 is (2, −1), so this IB sheet opens by evaluating functions and completing the square. The key gives x ≥ 3 for a domain and 9 for a later value.
Key Takeaways
f(5) = 17 when f(x) = 3x + 2 (Q1).
The vertex of y = x² − 4x + 3 is (2, −1) (Q2).
Q3 records the domain x ≥ 3.
Section A: Multiple Choice Questions (1 Mark Each)
Choose the correct option for each question.
1.If f(x) = 3x + 2, find f(5).
(a) 17(b) 13(c) 15(d) 21
2.What is the vertex of y = x² − 4x + 3?
(a) (2, −1)(b) (−1, 2)(c) (2, 1)(d) (−2, −3)
3.What is the domain of f(x) = √(x − 3)?
(a) x ≤ 3(b) x ≥ 3(c) x > 3(d) all real x
4.If f(x) = 2x + 1 and g(x) = x², find f(g(2)).
(a) 8(b) 5(c) 9(d) 16
5.What is the axis of symmetry of y = −2(x − 1)² + 5?